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(2b^2+3b-5)-(2b^2+4b-9=)
We move all terms to the left:
(2b^2+3b-5)-(2b^2+4b-9-())=0
We get rid of parentheses
2b^2+3b-(2b^2+4b-9-())-5=0
We calculate terms in parentheses: -(2b^2+4b-9-()), so:We get rid of parentheses
2b^2+4b-9-()
We add all the numbers together, and all the variables
2b^2+4b
Back to the equation:
-(2b^2+4b)
2b^2-2b^2+3b-4b-5=0
We add all the numbers together, and all the variables
-1b-5=0
We move all terms containing b to the left, all other terms to the right
-b=5
b=5/-1
b=-5
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